G'day Bob, Richard and fellow Aviators.
Bob I have to hand it to you, you have explained the differences between US and Australian Navigation well on Page 3.6 (issue 3 2009 BTCPLNAV) in terms of the words Course (US) and Track (Australia) both appearing to mean the same thing (path relative to the ground).
Also you make the point on the same page, that it is "JUST AS valid to change track and wind to magnetic BEFORE (caps mine) the calculation, given a magnetic heading for the answer. This is the method we shall adopt."
If you don't mind me asking so, WHY is this so? (I have also noticed the difference with US Pre Flight planning info having a True Course on a flight plan), given that the E6B computers that most of us use here in Australia are in fact American, and have a formula that one is supposed to use written on them that being:
TC (True Course) -L or + R WCA (Wind Correction Angle) = TH (True Heading) -E or +W VAR (Magnetic Variation)=MH (Magnetic Heading) -E or +W DEV (Compass Deviation)= CH (Compass Heading - the operational bit
Now the problem I am specifically having is two fold:
1) now that we are doing calcs another way I keep "tripping over" the legend on the E6B
2) when I go through the excercise table in Excercise N9 on page 3.8 my answers vary from those quoted, which is not helping my self esteem or navigational confidence, unless the one I singled out with a vengeance is erronious?
The Question I am focusing on (but having pains with) using the US formula above this time (as per the front face of the APR E6B flight computer I am using, in attempting to find the two answers of MAGNETIC HEADING that should be flown as well as the GROUND SPEED to expect (are you sure the two ways US vs Australia) both achieve exactly the same thing (excuse my naivety here)?
So I take the following details I have on Q5:
FPT of 260 deg M
VAR of 5 deg East
Forecast Wind deg True / kt 300deg TRUE /30kt
TAS 130 Kt
I then follow the instructions on the E6B VERBATIM:
1. SET WIND DIRECTION OPPOSITE (true index)
2. MARK W (Wind Dot) UP FROM G (Grommet)
3. PLACE TRUE COURSE UNDER(True Index)
4. SLIDE THE AIRSPEED UNDER W (Wind Dot)
5. READ GROUND SPEED UNDER G (Grommet)
6. READ WCA UNDER W (Wind Dot)
7. COMPLETE PROBLEM BY USE OF FORMULA (Quoted above in text)
So With my trusty E6B I: (steps to correspond with above manufacturer steps - this is the E6B that King Schools / Cessna Pilot Centers use as a preferred computer)
1) first of all line up the wind on 300 deg true, and
2) draw a line straight up from the "wind dot" which is 30 knots high, and place both a small cross (centre of cross is exactly at 30 kts) and also a line to join the cross with the dot. (so that gives me my 30 knots at 300 deg)
3) I now rotate the bezzle on my computer until the TRUE course is under (so to get the TRUE course from the FPT (260 deg mag) I simply adjust the FTP by - 5 deg VAR (since east is least) which brings my TRUE Course to 255 deg (TRUE) so I twist this course into the dial of the E6B.
4) Now I "slide the true airspeed under W (Wind Dot - in my case the centre of the cross is now sitting on the supplies TAS of 130)
5) I now read the groundspeed under G (Grommet) and come up with 107 knots GS exactly (and I am using a Papermate pencil with 0.5mm leads).
6)At this time I also noted a WCA of JUST over 9 deg to the right, so I settle on 9 degree WCA (not a water closet angle)
7) I now go about completing the problem by use of the formula above:
TC (True Course) -L or + R WCA (Wind Correction Angle) = TH (True Heading) -E or +W VAR (Magnetic Variation)=MH (Magnetic Heading) -E or +W DEV (Compass Deviation)= CH (Compass Heading
255 deg True + 9 deg (right WCA) = True Heading of 264 deg. I then take away the 5 degrees VAR (east is least) and end up with a MAGNETIC heading of 259 deg for the purpose of question 6. (I dont need to worry about compass dev or the resultant heading since the variables are not supplied nor computed for this question.
So my answers for Question 5 are as per my calculation: 259 deg magnetic and 107 knots GS.
Alas the answer quoted in the BT book is 268 magnetic and 105 knots. Now OK I can accept a tolerance of two knots Groundspeed but 9 degrees is way of course for the purposes of navigation.
Am I missing something here, its driving me nuts, and I had this issue on a couple of other questions as well, but I am getting correct answers off the E6B.
Any help greatly appreciated!